What are the solutions to the equation -4x=x^2+4 ?

The solutions to the equation -4x=x^2+4 are x=-2

Find the zeros of -4x=x^2+4

The zeros of -4x=x^2+4 are x=-2

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- 4 x = x^{2} + 4

x = - 2

Solution steps

- 4 x = x^{2} + 4

Switch sides

x^{2} + 4 = - 4 x

Move

4 x

to the left side

x^{2} + 4 + 4 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 4 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot 4 = 0

x_{1, 2} = \frac{- 4 \pm 0}{2 \cdot 1}

x = \frac{- 4}{2 \cdot 1}

\frac{- 4}{2 \cdot 1} = - 2

x = - 2

The solution to the quadratic equation is:

x = - 2

7^{2} + 4 2^{2} = c^{2}

10.4 (t^{2} - 6.2) = 24

4 x^{2} + 20 x + 25 = 0

(2 y - 3)^{2} = 5

3 x^{2} - 14 - 5 = 0

What are the solutions to the equation -4x=x^2+4 ?
The solutions to the equation -4x=x^2+4 are x=-2
Find the zeros of -4x=x^2+4
The zeros of -4x=x^2+4 are x=-2