What are the solutions to the equation 2x^2= x/3 ?

The solutions to the equation 2x^2= x/3 are x= 1/6 ,x=0

Find the zeros of 2x^2= x/3

The zeros of 2x^2= x/3 are x= 1/6 ,x=0

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2 x^{2} = \frac{x}{3}

x = \frac{1}{6}, x = 0

Decimal Notation

x = 0.16666 \dots, x = 0

Solution steps

2 x^{2} = \frac{x}{3}

Multiply both sides by

3

6 x^{2} = x

Move

x

to the left side

6 x^{2} - x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 6 \cdot 0}{2 \cdot 6}

(- 1)^{2} - 4 \cdot 6 \cdot 0 = 1

x_{1, 2} = \frac{- ( - 1 ) \pm 1}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 1}{2 \cdot 6}, x_{2} = \frac{- ( - 1 ) - 1}{2 \cdot 6}

x = \frac{- ( - 1 ) + 1}{2 \cdot 6} : \frac{1}{6}

x = \frac{- ( - 1 ) - 1}{2 \cdot 6} : 0

The solutions to the quadratic equation are:

x = \frac{1}{6}, x = 0

r^{2} = (- 5)^{2} + 1 2^{2}

k^{2} + 44 k = 0

9 q^{2} - 11 q + 2 = 3 q^{2}

7 x^{2} - 9 x + 3 = 0

(x + 2)^{2} + 3 = 0

What are the solutions to the equation 2x^2= x/3 ?
The solutions to the equation 2x^2= x/3 are x= 1/6 ,x=0
Find the zeros of 2x^2= x/3
The zeros of 2x^2= x/3 are x= 1/6 ,x=0