What are the solutions to the equation solvefor a,(a+b+c)^2=144 ?

The solutions to the equation solvefor a,(a+b+c)^2=144 are a=12-b-c,a=-12-b-c

Find the zeros of solvefor a,(a+b+c)^2=144

The zeros of solvefor a,(a+b+c)^2=144 are a=12-b-c,a=-12-b-c

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solve for

a, (a + b + c)^{2} = 144

a = 12 - b - c, a = - 12 - b - c

Solution steps

(a + b + c)^{2} = 144

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

a + b + c = 144 : a = 12 - b - c

Solve

a + b + c = - 144 : a = - 12 - b - c

The solutions to the quadratic equation are:

a = 12 - b - c, a = - 12 - b - c

2 w^{2} + 3 w - 35 = 0

0 = - 12 x^{2} + 4

x, 2 x^{2} + 3 y^{2} + x + 4 y + 5 = 0

11 x = 2 x^{2} + 12

7 x^{2} - (2 x - 3)^{2} = 3 (4 x - 1)

What are the solutions to the equation solvefor a,(a+b+c)^2=144 ?
The solutions to the equation solvefor a,(a+b+c)^2=144 are a=12-b-c,a=-12-b-c
Find the zeros of solvefor a,(a+b+c)^2=144
The zeros of solvefor a,(a+b+c)^2=144 are a=12-b-c,a=-12-b-c