What are the solutions to the equation 4x^2-20x-120=0 ?

The solutions to the equation 4x^2-20x-120=0 are x=(5+sqrt(145))/2 ,x=(5-sqrt(145))/2

Find the zeros of 4x^2-20x-120=0

The zeros of 4x^2-20x-120=0 are x=(5+sqrt(145))/2 ,x=(5-sqrt(145))/2

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4 x^{2} - 20 x - 120 = 0

x = \frac{5 + 145}{2}, x = \frac{5 - 145}{2}

Decimal Notation

x = 8.52079 \dots, x = - 3.52079 \dots

Solution steps

4 x^{2} - 20 x - 120 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 4 ( - 120 )}{2 \cdot 4}

(- 20)^{2} - 4 \cdot 4 (- 120) = 4145

x_{1, 2} = \frac{- ( - 20 ) \pm 4 145}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 4 145}{2 \cdot 4}, x_{2} = \frac{- ( - 20 ) - 4 145}{2 \cdot 4}

x = \frac{- ( - 20 ) + 4 145}{2 \cdot 4} : \frac{5 + 145}{2}

x = \frac{- ( - 20 ) - 4 145}{2 \cdot 4} : \frac{5 - 145}{2}

The solutions to the quadratic equation are:

x = \frac{5 + 145}{2}, x = \frac{5 - 145}{2}

b^{2} = - 1

y^{2} + (y + 5)^{2} - 5 = 16 (3 - y)

3244.8 = 3000 (1 + \frac{r}{1})^{2}

p, x^{2} - 2 p x + p^{2} + p - 6 = 0

3 x^{2} - 15 = 66

What are the solutions to the equation 4x^2-20x-120=0 ?
The solutions to the equation 4x^2-20x-120=0 are x=(5+sqrt(145))/2 ,x=(5-sqrt(145))/2
Find the zeros of 4x^2-20x-120=0
The zeros of 4x^2-20x-120=0 are x=(5+sqrt(145))/2 ,x=(5-sqrt(145))/2