What are the solutions to the equation 7x^2-2x+4=0 ?

The solutions to the equation 7x^2-2x+4=0 are x= 1/7+i(3sqrt(3))/7 ,x= 1/7-i(3sqrt(3))/7

Find the zeros of 7x^2-2x+4=0

The zeros of 7x^2-2x+4=0 are x= 1/7+i(3sqrt(3))/7 ,x= 1/7-i(3sqrt(3))/7

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7 x^{2} - 2 x + 4 = 0

x = \frac{1}{7} + i \frac{3 3}{7}, x = \frac{1}{7} - i \frac{3 3}{7}

Solution steps

7 x^{2} - 2 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 7 \cdot 4}{2 \cdot 7}

Simplify

(- 2)^{2} - 4 \cdot 7 \cdot 4 : 63 i

x_{1, 2} = \frac{- ( - 2 ) \pm 6 3 i}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 6 3 i}{2 \cdot 7}, x_{2} = \frac{- ( - 2 ) - 6 3 i}{2 \cdot 7}

x = \frac{- ( - 2 ) + 6 3 i}{2 \cdot 7} : \frac{1}{7} + i \frac{3 3}{7}

x = \frac{- ( - 2 ) - 6 3 i}{2 \cdot 7} : \frac{1}{7} - i \frac{3 3}{7}

The solutions to the quadratic equation are:

x = \frac{1}{7} + i \frac{3 3}{7}, x = \frac{1}{7} - i \frac{3 3}{7}

9 x^{2} - 64 z^{2}

4.5 x^{2} + 3 x + \frac{1}{2} = 0

\frac{80 + 12 + 28 + 20}{15}

- \frac{1}{4} + 1

7 a - 9 b + 6 a - 4 b

What are the solutions to the equation 7x^2-2x+4=0 ?
The solutions to the equation 7x^2-2x+4=0 are x= 1/7+i(3sqrt(3))/7 ,x= 1/7-i(3sqrt(3))/7
Find the zeros of 7x^2-2x+4=0
The zeros of 7x^2-2x+4=0 are x= 1/7+i(3sqrt(3))/7 ,x= 1/7-i(3sqrt(3))/7