What are the solutions to the equation 30=10+0.9v-0.01v^2 ?

The solutions to the equation 30=10+0.9v-0.01v^2 are v=40,v=50

Find the zeros of 30=10+0.9v-0.01v^2

The zeros of 30=10+0.9v-0.01v^2 are v=40,v=50

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30 = 10 + 0.9 v - 0.01 v^{2}

v = 40, v = 50

Solution steps

30 = 10 + 0.9 v - 0.01 v^{2}

Multiply both sides by

100

3000 = 1000 + 90 v - v^{2}

Switch sides

1000 + 90 v - v^{2} = 3000

Move

3000

to the left side

- v^{2} + 90 v - 2000 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- 90 \pm 9 0 ^{2} - 4 ( - 1 ) ( - 2000 )}{2 ( - 1 )}

9 0^{2} - 4 (- 1) (- 2000) = 10

v_{1, 2} = \frac{- 90 \pm 10}{2 ( - 1 )}

Separate the solutions

v_{1} = \frac{- 90 + 10}{2 ( - 1 )}, v_{2} = \frac{- 90 - 10}{2 ( - 1 )}

v = \frac{- 90 + 10}{2 ( - 1 )} : 40

v = \frac{- 90 - 10}{2 ( - 1 )} : 50

The solutions to the quadratic equation are:

v = 40, v = 50

z^{2} + z - 72 = 0

x^{2} + 12 x - 16 = 0

p^{2} + 9 p + 20 = 0

4 - y = y^{2} - 4 y + 4

0.8 (26977.5) = 75 x^{2}

What are the solutions to the equation 30=10+0.9v-0.01v^2 ?
The solutions to the equation 30=10+0.9v-0.01v^2 are v=40,v=50
Find the zeros of 30=10+0.9v-0.01v^2
The zeros of 30=10+0.9v-0.01v^2 are v=40,v=50