What are the solutions to the equation x^2-10x+19=3 ?

The solutions to the equation x^2-10x+19=3 are x=8,x=2

Find the zeros of x^2-10x+19=3

The zeros of x^2-10x+19=3 are x=8,x=2

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x^{2} - 10 x + 19 = 3

x = 8, x = 2

Solution steps

x^{2} - 10 x + 19 = 3

Move

3

to the left side

x^{2} - 10 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 16}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 16 = 6

x_{1, 2} = \frac{- ( - 10 ) \pm 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 6}{2 \cdot 1}, x_{2} = \frac{- ( - 10 ) - 6}{2 \cdot 1}

x = \frac{- ( - 10 ) + 6}{2 \cdot 1} : 8

x = \frac{- ( - 10 ) - 6}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

x = 8, x = 2

x, I n (- x) = I n (x^{2} - 6)

(0.3 - x) (1.1 - x) - (- 0.3) (0.4) = 0

- 6 x^{2} + 48 x = 0

n^{2} + 9 n + 18 = 0

y, x^{3} - 3 x y^{2} = 1

What are the solutions to the equation x^2-10x+19=3 ?
The solutions to the equation x^2-10x+19=3 are x=8,x=2
Find the zeros of x^2-10x+19=3
The zeros of x^2-10x+19=3 are x=8,x=2