What are the solutions to the equation 12x^2-104x+168=0 ?

The solutions to the equation 12x^2-104x+168=0 are x=(13+sqrt(43))/3 ,x=(13-sqrt(43))/3

Find the zeros of 12x^2-104x+168=0

The zeros of 12x^2-104x+168=0 are x=(13+sqrt(43))/3 ,x=(13-sqrt(43))/3

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12 x^{2} - 104 x + 168 = 0

x = \frac{13 + 43}{3}, x = \frac{13 - 43}{3}

Decimal Notation

x = 6.51914 \dots, x = 2.14752 \dots

Solution steps

12 x^{2} - 104 x + 168 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 104 ) \pm ( - 104 ) ^{2} - 4 \cdot 12 \cdot 168}{2 \cdot 12}

(- 104)^{2} - 4 \cdot 12 \cdot 168 = 843

x_{1, 2} = \frac{- ( - 104 ) \pm 8 43}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 104 ) + 8 43}{2 \cdot 12}, x_{2} = \frac{- ( - 104 ) - 8 43}{2 \cdot 12}

x = \frac{- ( - 104 ) + 8 43}{2 \cdot 12} : \frac{13 + 43}{3}

x = \frac{- ( - 104 ) - 8 43}{2 \cdot 12} : \frac{13 - 43}{3}

The solutions to the quadratic equation are:

x = \frac{13 + 43}{3}, x = \frac{13 - 43}{3}

- 36 x^{2} = 0

p^{2} = 40

- 5 x^{2} + 7 x + 9 = 0

(x + 6) (x - 2) = 0

- 10 x^{2} = 0

What are the solutions to the equation 12x^2-104x+168=0 ?
The solutions to the equation 12x^2-104x+168=0 are x=(13+sqrt(43))/3 ,x=(13-sqrt(43))/3
Find the zeros of 12x^2-104x+168=0
The zeros of 12x^2-104x+168=0 are x=(13+sqrt(43))/3 ,x=(13-sqrt(43))/3