What are the solutions to the equation 300=(75x-0.5x^2)-(35x+300) ?

The solutions to the equation 300=(75x-0.5x^2)-(35x+300) are x=20,x=60

Find the zeros of 300=(75x-0.5x^2)-(35x+300)

The zeros of 300=(75x-0.5x^2)-(35x+300) are x=20,x=60

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300 = (75 x - 0.5 x^{2}) - (35 x + 300)

x = 20, x = 60

Solution steps

300 = (75 x - 0.5 x^{2}) - (35 x + 300)

Expand

(75 x - 0.5 x^{2}) - (35 x + 300) : - 0.5 x^{2} + 40 x - 300

300 = - 0.5 x^{2} + 40 x - 300

Switch sides

- 0.5 x^{2} + 40 x - 300 = 300

Move

300

to the left side

- 0.5 x^{2} + 40 x - 600 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 40 \pm 4 0 ^{2} - 4 ( - 0.5 ) ( - 600 )}{2 ( - 0.5 )}

4 0^{2} - 4 (- 0.5) (- 600) = 20

x_{1, 2} = \frac{- 40 \pm 20}{2 ( - 0.5 )}

Separate the solutions

x_{1} = \frac{- 40 + 20}{2 ( - 0.5 )}, x_{2} = \frac{- 40 - 20}{2 ( - 0.5 )}

x = \frac{- 40 + 20}{2 ( - 0.5 )} : 20

x = \frac{- 40 - 20}{2 ( - 0.5 )} : 60

The solutions to the quadratic equation are:

x = 20, x = 60

3 x^{2} - 8 = 4

2 y^{2} - 2 y - 4 = 0

x^{2} + 5 x = 1

9 x^{2} = - 7 x

x, x^{2} + x y + y^{2} = 6

What are the solutions to the equation 300=(75x-0.5x^2)-(35x+300) ?
The solutions to the equation 300=(75x-0.5x^2)-(35x+300) are x=20,x=60
Find the zeros of 300=(75x-0.5x^2)-(35x+300)
The zeros of 300=(75x-0.5x^2)-(35x+300) are x=20,x=60