What are the solutions to the equation 3(x^2-4x+3)=0 ?

The solutions to the equation 3(x^2-4x+3)=0 are x=1,x=3

Find the zeros of 3(x^2-4x+3)=0

The zeros of 3(x^2-4x+3)=0 are x=1,x=3

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3 (x^{2} - 4 x + 3) = 0

x = 1, x = 3

Solution steps

3 (x^{2} - 4 x + 3) = 0

Factor

3 (x^{2} - 4 x + 3) : 3 (x - 1) (x - 3)

3 (x - 1) (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or x - 3 = 0

Solve

x - 1 = 0 : x = 1

Solve

x - 3 = 0 : x = 3

The solutions to the quadratic equation are:

x = 1, x = 3

- (x - 11) (x + 3) = 0

(2 n + 3)^{2} = (3 n + 2)^{2}

x^{2} - 14 x + 49

x^{2} - 14 x + 40

3 (x + 2)^{2} = 30

What are the solutions to the equation 3(x^2-4x+3)=0 ?
The solutions to the equation 3(x^2-4x+3)=0 are x=1,x=3
Find the zeros of 3(x^2-4x+3)=0
The zeros of 3(x^2-4x+3)=0 are x=1,x=3