What are the solutions to the equation 0=2m-3m^2 ?

The solutions to the equation 0=2m-3m^2 are m=0,m= 2/3

Find the zeros of 0=2m-3m^2

The zeros of 0=2m-3m^2 are m=0,m= 2/3

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0 = 2 m - 3 m^{2}

m = 0, m = \frac{2}{3}

Decimal Notation

m = 0, m = 0.66666 \dots

Solution steps

0 = 2 m - 3 m^{2}

Switch sides

2 m - 3 m^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 3 m^{2} + 2 m = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 ( - 3 ) \cdot 0}{2 ( - 3 )}

2^{2} - 4 (- 3) \cdot 0 = 2

m_{1, 2} = \frac{- 2 \pm 2}{2 ( - 3 )}

Separate the solutions

m_{1} = \frac{- 2 + 2}{2 ( - 3 )}, m_{2} = \frac{- 2 - 2}{2 ( - 3 )}

m = \frac{- 2 + 2}{2 ( - 3 )} : 0

m = \frac{- 2 - 2}{2 ( - 3 )} : \frac{2}{3}

The solutions to the quadratic equation are:

m = 0, m = \frac{2}{3}

3 x + 4 = x^{2}

a x^{2} + 5 x + c = 0

z^{2} + 3 z + 3 = 0

44 = \frac{n ( n - 3 )}{2}

15 x^{2} - 34 x - 16 = 0

What are the solutions to the equation 0=2m-3m^2 ?
The solutions to the equation 0=2m-3m^2 are m=0,m= 2/3
Find the zeros of 0=2m-3m^2
The zeros of 0=2m-3m^2 are m=0,m= 2/3