What are the solutions to the equation 3x(x-8)+2(x-7)=2 ?

The solutions to the equation 3x(x-8)+2(x-7)=2 are x=8,x=-2/3

Find the zeros of 3x(x-8)+2(x-7)=2

The zeros of 3x(x-8)+2(x-7)=2 are x=8,x=-2/3

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3 x (x - 8) + 2 (x - 7) = 2

x = 8, x = - \frac{2}{3}

Decimal Notation

x = 8, x = - 0.66666 \dots

Solution steps

3 x (x - 8) + 2 (x - 7) = 2

Expand

3 x (x - 8) + 2 (x - 7) : 3 x^{2} - 22 x - 14

3 x^{2} - 22 x - 14 = 2

Move

2

to the left side

3 x^{2} - 22 x - 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 22 ) \pm ( - 22 ) ^{2} - 4 \cdot 3 ( - 16 )}{2 \cdot 3}

(- 22)^{2} - 4 \cdot 3 (- 16) = 26

x_{1, 2} = \frac{- ( - 22 ) \pm 26}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 22 ) + 26}{2 \cdot 3}, x_{2} = \frac{- ( - 22 ) - 26}{2 \cdot 3}

x = \frac{- ( - 22 ) + 26}{2 \cdot 3} : 8

x = \frac{- ( - 22 ) - 26}{2 \cdot 3} : - \frac{2}{3}

The solutions to the quadratic equation are:

x = 8, x = - \frac{2}{3}

- 8 x^{2} + 2 x = 5

y, z = x^{3} + 4 x y - 3 y^{2}

x, x^{2} - 3 x y + 5 y^{2} - 4 = 0

- 16 x^{2} + 144 x + 108 = 0

y, x^{3} + x y^{2} = 5

What are the solutions to the equation 3x(x-8)+2(x-7)=2 ?
The solutions to the equation 3x(x-8)+2(x-7)=2 are x=8,x=-2/3
Find the zeros of 3x(x-8)+2(x-7)=2
The zeros of 3x(x-8)+2(x-7)=2 are x=8,x=-2/3