What are the solutions to the equation (4+x)3x=48 ?

The solutions to the equation (4+x)3x=48 are x=2(sqrt(5)-1),x=-2(1+sqrt(5))

Find the zeros of (4+x)3x=48

The zeros of (4+x)3x=48 are x=2(sqrt(5)-1),x=-2(1+sqrt(5))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(4 + x) 3 x = 48

x = 2 (5 - 1), x = - 2 (1 + 5)

Decimal Notation

x = 2.47213 \dots, x = - 6.47213 \dots

Solution steps

(4 + x) \cdot 3 x = 48

Expand

(4 + x) \cdot 3 x : 12 x + 3 x^{2}

12 x + 3 x^{2} = 48

Move

48

to the left side

12 x + 3 x^{2} - 48 = 0

Write in the standard form

a x^{2} + b x + c = 0

3 x^{2} + 12 x - 48 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 3 ( - 48 )}{2 \cdot 3}

1 2^{2} - 4 \cdot 3 (- 48) = 125

x_{1, 2} = \frac{- 12 \pm 12 5}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 12 + 12 5}{2 \cdot 3}, x_{2} = \frac{- 12 - 12 5}{2 \cdot 3}

x = \frac{- 12 + 12 5}{2 \cdot 3} : 2 (5 - 1)

x = \frac{- 12 - 12 5}{2 \cdot 3} : - 2 (1 + 5)

The solutions to the quadratic equation are:

x = 2 (5 - 1), x = - 2 (1 + 5)

9 y^{2} - 49 = 0

x, x^{2} + 8 x + 11 = 0

x^{2} = - 7 - 16 x

x^{2} - 13 x - 42 = 0

4.4 \cdot 1 0^{- 4} = \frac{x ^{2}}{0.14}

What are the solutions to the equation (4+x)3x=48 ?
The solutions to the equation (4+x)3x=48 are x=2(sqrt(5)-1),x=-2(1+sqrt(5))
Find the zeros of (4+x)3x=48
The zeros of (4+x)3x=48 are x=2(sqrt(5)-1),x=-2(1+sqrt(5))