What are the solutions to the equation 4k(k+6)=6 ?

The solutions to the equation 4k(k+6)=6 are k=(-6+sqrt(42))/2 ,k=-(6+sqrt(42))/2

Find the zeros of 4k(k+6)=6

The zeros of 4k(k+6)=6 are k=(-6+sqrt(42))/2 ,k=-(6+sqrt(42))/2

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4 k (k + 6) = 6

k = \frac{- 6 + 42}{2}, k = - \frac{6 + 42}{2}

Decimal Notation

k = 0.24037 \dots, k = - 6.24037 \dots

Solution steps

4 k (k + 6) = 6

Expand

4 k (k + 6) : 4 k^{2} + 24 k

4 k^{2} + 24 k = 6

Move

6

to the left side

4 k^{2} + 24 k - 6 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 4 ( - 6 )}{2 \cdot 4}

2 4^{2} - 4 \cdot 4 (- 6) = 442

k_{1, 2} = \frac{- 24 \pm 4 42}{2 \cdot 4}

Separate the solutions

k_{1} = \frac{- 24 + 4 42}{2 \cdot 4}, k_{2} = \frac{- 24 - 4 42}{2 \cdot 4}

k = \frac{- 24 + 4 42}{2 \cdot 4} : \frac{- 6 + 42}{2}

k = \frac{- 24 - 4 42}{2 \cdot 4} : - \frac{6 + 42}{2}

The solutions to the quadratic equation are:

k = \frac{- 6 + 42}{2}, k = - \frac{6 + 42}{2}

x^{2} - 2 x = - 8 x

120 - q^{2} = 32 + 3 q

x^{2} - 2 x = - 63

2 x^{2} - 4 a x + b x = 2 ab

\frac{3 x - 4}{2} = \frac{x ^{2} + 1}{5}

What are the solutions to the equation 4k(k+6)=6 ?
The solutions to the equation 4k(k+6)=6 are k=(-6+sqrt(42))/2 ,k=-(6+sqrt(42))/2
Find the zeros of 4k(k+6)=6
The zeros of 4k(k+6)=6 are k=(-6+sqrt(42))/2 ,k=-(6+sqrt(42))/2