What are the solutions to the equation (x+2)^2+9=0 ?

The solutions to the equation (x+2)^2+9=0 are x=3i-2,x=-3i-2

Find the zeros of (x+2)^2+9=0

The zeros of (x+2)^2+9=0 are x=3i-2,x=-3i-2

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(x + 2)^{2} + 9 = 0

x = 3 i - 2, x = - 3 i - 2

Solution steps

(x + 2)^{2} + 9 = 0

Move

9

to the right side

(x + 2)^{2} = - 9

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 2 = - 9 : x = 3 i - 2

Solve

x + 2 = - - 9 : x = - 3 i - 2

The solutions to the quadratic equation are:

x = 3 i - 2, x = - 3 i - 2

x^{2} + x - 17 = 0

x^{2} + 4.37 x - 21.28 = 0

(2 x - 1)^{2} + 5 = - 23

\frac{( x - 2 ) ^{2}}{2} + 2 (2 - x) = 4

3 x^{2} - 12 x = 6

What are the solutions to the equation (x+2)^2+9=0 ?
The solutions to the equation (x+2)^2+9=0 are x=3i-2,x=-3i-2
Find the zeros of (x+2)^2+9=0
The zeros of (x+2)^2+9=0 are x=3i-2,x=-3i-2