What are the solutions to the equation 2x^2-8x=16 ?

The solutions to the equation 2x^2-8x=16 are x=2(1+sqrt(3)),x=2(1-sqrt(3))

Find the zeros of 2x^2-8x=16

The zeros of 2x^2-8x=16 are x=2(1+sqrt(3)),x=2(1-sqrt(3))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} - 8 x = 16

x = 2 (1 + 3), x = 2 (1 - 3)

Decimal Notation

x = 5.46410 \dots, x = - 1.46410 \dots

Solution steps

2 x^{2} - 8 x = 16

Move

16

to the left side

2 x^{2} - 8 x - 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 2 ( - 16 )}{2 \cdot 2}

(- 8)^{2} - 4 \cdot 2 (- 16) = 83

x_{1, 2} = \frac{- ( - 8 ) \pm 8 3}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 8 3}{2 \cdot 2}, x_{2} = \frac{- ( - 8 ) - 8 3}{2 \cdot 2}

x = \frac{- ( - 8 ) + 8 3}{2 \cdot 2} : 2 (1 + 3)

x = \frac{- ( - 8 ) - 8 3}{2 \cdot 2} : 2 (1 - 3)

The solutions to the quadratic equation are:

x = 2 (1 + 3), x = 2 (1 - 3)

x^{2} = 3^{2} + 8^{2}

x, (x + 5)^{2} + (y - 5)^{2} = 0

(3 x - 1)^{2} = 25

12 x^{2} - 452 x + 2850 = 0

x (x - 3) = 3 x

What are the solutions to the equation 2x^2-8x=16 ?
The solutions to the equation 2x^2-8x=16 are x=2(1+sqrt(3)),x=2(1-sqrt(3))
Find the zeros of 2x^2-8x=16
The zeros of 2x^2-8x=16 are x=2(1+sqrt(3)),x=2(1-sqrt(3))