What are the solutions to the equation 3k^2+3k-3=0 ?

The solutions to the equation 3k^2+3k-3=0 are k=(-1+sqrt(5))/2 ,k=-(1+sqrt(5))/2

Find the zeros of 3k^2+3k-3=0

The zeros of 3k^2+3k-3=0 are k=(-1+sqrt(5))/2 ,k=-(1+sqrt(5))/2

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3 k^{2} + 3 k - 3 = 0

k = \frac{- 1 + 5}{2}, k = - \frac{1 + 5}{2}

Decimal Notation

k = 0.61803 \dots, k = - 1.61803 \dots

Solution steps

3 k^{2} + 3 k - 3 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 3 ( - 3 )}{2 \cdot 3}

3^{2} - 4 \cdot 3 (- 3) = 35

k_{1, 2} = \frac{- 3 \pm 3 5}{2 \cdot 3}

Separate the solutions

k_{1} = \frac{- 3 + 3 5}{2 \cdot 3}, k_{2} = \frac{- 3 - 3 5}{2 \cdot 3}

k = \frac{- 3 + 3 5}{2 \cdot 3} : \frac{- 1 + 5}{2}

k = \frac{- 3 - 3 5}{2 \cdot 3} : - \frac{1 + 5}{2}

The solutions to the quadratic equation are:

k = \frac{- 1 + 5}{2}, k = - \frac{1 + 5}{2}

- \frac{20}{4}

∣ u ∣ - 14 = - 5

\frac{- 1}{2} > \frac{- 1}{5}

x + 7 > 12

(- 53)^{2}

What are the solutions to the equation 3k^2+3k-3=0 ?
The solutions to the equation 3k^2+3k-3=0 are k=(-1+sqrt(5))/2 ,k=-(1+sqrt(5))/2
Find the zeros of 3k^2+3k-3=0
The zeros of 3k^2+3k-3=0 are k=(-1+sqrt(5))/2 ,k=-(1+sqrt(5))/2