What are the solutions to the equation quadraticformula x^2+11x+24=0 ?

The solutions to the equation quadraticformula x^2+11x+24=0 are x=-3,x=-8

Find the zeros of quadraticformula x^2+11x+24=0

The zeros of quadraticformula x^2+11x+24=0 are x=-3,x=-8

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x^{2} + 11 x + 24 = 0

x = - 3, x = - 8

Solution steps

x^{2} + 11 x + 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 1 \cdot 24}{2 \cdot 1}

1 1^{2} - 4 \cdot 1 \cdot 24 = 5

x_{1, 2} = \frac{- 11 \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 11 + 5}{2 \cdot 1}, x_{2} = \frac{- 11 - 5}{2 \cdot 1}

x = \frac{- 11 + 5}{2 \cdot 1} : - 3

x = \frac{- 11 - 5}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

x = - 3, x = - 8

2 x^{2} - 5 x - 3 = 0

18 k^{2} = 50

x^{2} - 10 x - 3

2 x^{2} + 5 x + 7

(x - 1) (x + 2) = 4

What are the solutions to the equation quadraticformula x^2+11x+24=0 ?
The solutions to the equation quadraticformula x^2+11x+24=0 are x=-3,x=-8
Find the zeros of quadraticformula x^2+11x+24=0
The zeros of quadraticformula x^2+11x+24=0 are x=-3,x=-8