What are the solutions to the equation 2u^2+u-1=0 ?

The solutions to the equation 2u^2+u-1=0 are u= 1/2 ,u=-1

Find the zeros of 2u^2+u-1=0

The zeros of 2u^2+u-1=0 are u= 1/2 ,u=-1

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2 u^{2} + u - 1 = 0

u = \frac{1}{2}, u = - 1

Decimal Notation

u = 0.5, u = - 1

Solution steps

2 u^{2} + u - 1 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 2 ( - 1 )}{2 \cdot 2}

1^{2} - 4 \cdot 2 (- 1) = 3

u_{1, 2} = \frac{- 1 \pm 3}{2 \cdot 2}

Separate the solutions

u_{1} = \frac{- 1 + 3}{2 \cdot 2}, u_{2} = \frac{- 1 - 3}{2 \cdot 2}

u = \frac{- 1 + 3}{2 \cdot 2} : \frac{1}{2}

u = \frac{- 1 - 3}{2 \cdot 2} : - 1

The solutions to the quadratic equation are:

u = \frac{1}{2}, u = - 1

s^{2} + 12 s + 400 = 0

x^{2} + 37 x = 0

- 0.5 a^{2} + 243 a - 3280.5 = 0

2 a - 4 x = x^{2} + a^{2} - 4

0.0493 x^{2} - 0.9621 x + 53.104 - 70 = 0

What are the solutions to the equation 2u^2+u-1=0 ?
The solutions to the equation 2u^2+u-1=0 are u= 1/2 ,u=-1
Find the zeros of 2u^2+u-1=0
The zeros of 2u^2+u-1=0 are u= 1/2 ,u=-1