What are the solutions to the equation d^2+34d=0 ?

The solutions to the equation d^2+34d=0 are d=0,d=-34

Find the zeros of d^2+34d=0

The zeros of d^2+34d=0 are d=0,d=-34

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d^{2} + 34 d = 0

d = 0, d = - 34

Solution steps

d^{2} + 34 d = 0

Solve with the quadratic formula

d_{1, 2} = \frac{- 34 \pm 3 4 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

3 4^{2} - 4 \cdot 1 \cdot 0 = 34

d_{1, 2} = \frac{- 34 \pm 34}{2 \cdot 1}

Separate the solutions

d_{1} = \frac{- 34 + 34}{2 \cdot 1}, d_{2} = \frac{- 34 - 34}{2 \cdot 1}

d = \frac{- 34 + 34}{2 \cdot 1} : 0

d = \frac{- 34 - 34}{2 \cdot 1} : - 34

The solutions to the quadratic equation are:

d = 0, d = - 34

7 x^{2} + 29 x - 30 = 0

(x - 7)^{2} = - 64

(x + 8)^{2} = 36

2 x^{2} + 7 x + 3 = 0

(x + 8)^{2} = 49

What are the solutions to the equation d^2+34d=0 ?
The solutions to the equation d^2+34d=0 are d=0,d=-34
Find the zeros of d^2+34d=0
The zeros of d^2+34d=0 are d=0,d=-34