What are the solutions to the equation -6+7x-x^2=0 ?

The solutions to the equation -6+7x-x^2=0 are x=1,x=6

Find the zeros of -6+7x-x^2=0

The zeros of -6+7x-x^2=0 are x=1,x=6

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- 6 + 7 x - x^{2} = 0

x = 1, x = 6

Solution steps

- 6 + 7 x - x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- x^{2} + 7 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 ( - 1 ) ( - 6 )}{2 ( - 1 )}

7^{2} - 4 (- 1) (- 6) = 5

x_{1, 2} = \frac{- 7 \pm 5}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 7 + 5}{2 ( - 1 )}, x_{2} = \frac{- 7 - 5}{2 ( - 1 )}

x = \frac{- 7 + 5}{2 ( - 1 )} : 1

x = \frac{- 7 - 5}{2 ( - 1 )} : 6

The solutions to the quadratic equation are:

x = 1, x = 6

2 x^{2} + 2 x - 2 = 5 x

2 x^{2} + 4 x - 16 = 0

r^{2} + 2 r - 24 = 0

(x + 2)^{2} + x = 0

x^{2} - 2 x - 16 = 0

What are the solutions to the equation -6+7x-x^2=0 ?
The solutions to the equation -6+7x-x^2=0 are x=1,x=6
Find the zeros of -6+7x-x^2=0
The zeros of -6+7x-x^2=0 are x=1,x=6