What are the solutions to the equation 7=pir^2 ?

The solutions to the equation 7=pir^2 are r=sqrt(7/pi),r=-sqrt(7/pi)

Find the zeros of 7=pir^2

The zeros of 7=pir^2 are r=sqrt(7/pi),r=-sqrt(7/pi)

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7 = π r^{2}

r = \frac{7}{π}, r = - \frac{7}{π}

Decimal Notation

r = 1.49270 \dots, r = - 1.49270 \dots

Solution steps

7 = π r^{2}

Switch sides

π r^{2} = 7

Divide both sides by

π

r^{2} = \frac{7}{π}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

r = \frac{7}{π}, r = - \frac{7}{π}

\frac{3}{4} x \cdot \frac{1}{12} x = x

x^{2} + x - 25 = 0

x^{2} - 16 + 48 = 0

w^{2} - 13 w + 40 = 0

x^{2} + 11 = 3 x

What are the solutions to the equation 7=pir^2 ?
The solutions to the equation 7=pir^2 are r=sqrt(7/pi),r=-sqrt(7/pi)
Find the zeros of 7=pir^2
The zeros of 7=pir^2 are r=sqrt(7/pi),r=-sqrt(7/pi)