What are the solutions to the equation solvefor b,a^3-ab^2-ac^2-abc+b^2c+bc^2=0 ?

The solutions to the equation solvefor b,a^3-ab^2-ac^2-abc+b^2c+bc^2=0 are

Find the zeros of solvefor b,a^3-ab^2-ac^2-abc+b^2c+bc^2=0

The zeros of solvefor b,a^3-ab^2-ac^2-abc+b^2c+bc^2=0 are

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solve for

b, a^{3} - a b^{2} - a c^{2} - ab c + b^{2} c + b c^{2} = 0

b = \frac{a c - c ^{2} + 4 a ^{4} - 4 a ^{3} c - 3 a ^{2} c ^{2} + 2 a c ^{3} + c ^{4}}{2 ( - a + c )}, b = \frac{a c - c ^{2} - 4 a ^{4} - 4 a ^{3} c - 3 a ^{2} c ^{2} + 2 a c ^{3} + c ^{4}}{2 ( - a + c )}; - a + c \neq = 0

Solution steps

a^{3} - a b^{2} - a c^{2} - ab c + b^{2} c + b c^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

(- a + c) b^{2} + (- a c + c^{2}) b + a^{3} - a c^{2} = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- ( - a c + c ^{2} ) \pm ( - a c + c ^{2} ) ^{2} - 4 ( - a + c ) ( a ^{3} - a c ^{2} )}{2 ( - a + c )}

Simplify

(- a c + c^{2})^{2} - 4 (- a + c) (a^{3} - a c^{2}) : 4 a^{4} - 4 a^{3} c - 3 a^{2} c^{2} + 2 a c^{3} + c^{4}

b_{1, 2} = \frac{- ( - a c + c ^{2} ) \pm 4 a ^{4} - 4 a ^{3} c - 3 a ^{2} c ^{2} + 2 a c ^{3} + c ^{4}}{2 ( - a + c )}; - a + c \neq = 0

Separate the solutions

b_{1} = \frac{- ( - a c + c ^{2} ) + 4 a ^{4} - 4 a ^{3} c - 3 a ^{2} c ^{2} + 2 a c ^{3} + c ^{4}}{2 ( - a + c )}, b_{2} = \frac{- ( - a c + c ^{2} ) - 4 a ^{4} - 4 a ^{3} c - 3 a ^{2} c ^{2} + 2 a c ^{3} + c ^{4}}{2 ( - a + c )}

b = \frac{- ( - a c + c ^{2} ) + 4 a ^{4} - 4 a ^{3} c - 3 a ^{2} c ^{2} + 2 a c ^{3} + c ^{4}}{2 ( - a + c )} : \frac{a c - c ^{2} + 4 a ^{4} - 4 a ^{3} c - 3 a ^{2} c ^{2} + 2 a c ^{3} + c ^{4}}{2 ( - a + c )}

b = \frac{- ( - a c + c ^{2} ) - 4 a ^{4} - 4 a ^{3} c - 3 a ^{2} c ^{2} + 2 a c ^{3} + c ^{4}}{2 ( - a + c )} : \frac{a c - c ^{2} - 4 a ^{4} - 4 a ^{3} c - 3 a ^{2} c ^{2} + 2 a c ^{3} + c ^{4}}{2 ( - a + c )}

The solutions to the quadratic equation are:

b = \frac{a c - c ^{2} + 4 a ^{4} - 4 a ^{3} c - 3 a ^{2} c ^{2} + 2 a c ^{3} + c ^{4}}{2 ( - a + c )}, b = \frac{a c - c ^{2} - 4 a ^{4} - 4 a ^{3} c - 3 a ^{2} c ^{2} + 2 a c ^{3} + c ^{4}}{2 ( - a + c )}; - a + c \neq = 0

x^{2} - 13 + 12 = 0

8 x^{2} - 10 x + 2 = 0

x, (x - 3)^{2} + (y + 5)^{2} + z^{2} = 81

3 (2 x + 5)^{2} = (2 x - 5)^{2} + 10

4 x^{2} = 2 x + 3

What are the solutions to the equation solvefor b,a^3-ab^2-ac^2-abc+b^2c+bc^2=0 ?
The solutions to the equation solvefor b,a^3-ab^2-ac^2-abc+b^2c+bc^2=0 are
Find the zeros of solvefor b,a^3-ab^2-ac^2-abc+b^2c+bc^2=0
The zeros of solvefor b,a^3-ab^2-ac^2-abc+b^2c+bc^2=0 are