What are the solutions to the equation (z+4)^2=7 ?

The solutions to the equation (z+4)^2=7 are z=sqrt(7)-4,z=-sqrt(7)-4

Find the zeros of (z+4)^2=7

The zeros of (z+4)^2=7 are z=sqrt(7)-4,z=-sqrt(7)-4

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(z + 4)^{2} = 7

z = 7 - 4, z = - 7 - 4

Decimal Notation

z = - 1.35424 \dots, z = - 6.64575 \dots

Solution steps

(z + 4)^{2} = 7

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

z + 4 = 7 : z = 7 - 4

Solve

z + 4 = - 7 : z = - 7 - 4

The solutions to the quadratic equation are:

z = 7 - 4, z = - 7 - 4

15 x^{2} + 8 x - 100 = 0

3 v^{2} + 12 v - 25 = - 10

x^{2} + 11 = 8 x

18 x^{2} = - 27 x

10 x^{2} - 13 x - 6 = 0

What are the solutions to the equation (z+4)^2=7 ?
The solutions to the equation (z+4)^2=7 are z=sqrt(7)-4,z=-sqrt(7)-4
Find the zeros of (z+4)^2=7
The zeros of (z+4)^2=7 are z=sqrt(7)-4,z=-sqrt(7)-4