What are the solutions to the equation q^2+6q+9=0 ?

The solutions to the equation q^2+6q+9=0 are q=-3

Find the zeros of q^2+6q+9=0

The zeros of q^2+6q+9=0 are q=-3

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q^{2} + 6 q + 9 = 0

q = - 3

Solution steps

q^{2} + 6 q + 9 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot 9 = 0

q_{1, 2} = \frac{- 6 \pm 0}{2 \cdot 1}

q = \frac{- 6}{2 \cdot 1}

\frac{- 6}{2 \cdot 1} = - 3

q = - 3

The solution to the quadratic equation is:

q = - 3

y, x = y^{2} + 2 b y - b^{2}

x (x + 10) = 144

x, 6 x^{2} - y^{2} = 0

x (x - 5) + \frac{3}{2} = 2

\frac{1}{3} x^{2} - 2 x - 2 = 0

What are the solutions to the equation q^2+6q+9=0 ?
The solutions to the equation q^2+6q+9=0 are q=-3
Find the zeros of q^2+6q+9=0
The zeros of q^2+6q+9=0 are q=-3