What are the solutions to the equation x^2+20x+5=0 ?

The solutions to the equation x^2+20x+5=0 are x=-10+sqrt(95),x=-10-sqrt(95)

Find the zeros of x^2+20x+5=0

The zeros of x^2+20x+5=0 are x=-10+sqrt(95),x=-10-sqrt(95)

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x^{2} + 20 x + 5 = 0

x = - 10 + 95, x = - 10 - 95

Decimal Notation

x = - 0.25320 \dots, x = - 19.74679 \dots

Solution steps

x^{2} + 20 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

2 0^{2} - 4 \cdot 1 \cdot 5 = 295

x_{1, 2} = \frac{- 20 \pm 2 95}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 20 + 2 95}{2 \cdot 1}, x_{2} = \frac{- 20 - 2 95}{2 \cdot 1}

x = \frac{- 20 + 2 95}{2 \cdot 1} : - 10 + 95

x = \frac{- 20 - 2 95}{2 \cdot 1} : - 10 - 95

The solutions to the quadratic equation are:

x = - 10 + 95, x = - 10 - 95

(x + 1)^{2} - 4 x = 1

124 = - 16 t^{2} + 100 t + 10

2 x^{2} + 5 x + 2 = 0

x, y = - 48.141 x^{2} + 39.476 x

12 x^{2} - 120 x + 225 = 0

What are the solutions to the equation x^2+20x+5=0 ?
The solutions to the equation x^2+20x+5=0 are x=-10+sqrt(95),x=-10-sqrt(95)
Find the zeros of x^2+20x+5=0
The zeros of x^2+20x+5=0 are x=-10+sqrt(95),x=-10-sqrt(95)