What are the solutions to the equation (4x-1)(x-1)=8-2x ?

The solutions to the equation (4x-1)(x-1)=8-2x are x= 7/4 ,x=-1

Find the zeros of (4x-1)(x-1)=8-2x

The zeros of (4x-1)(x-1)=8-2x are x= 7/4 ,x=-1

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(4 x - 1) (x - 1) = 8 - 2 x

x = \frac{7}{4}, x = - 1

Decimal Notation

x = 1.75, x = - 1

Solution steps

(4 x - 1) (x - 1) = 8 - 2 x

Expand

(4 x - 1) (x - 1) : 4 x^{2} - 5 x + 1

4 x^{2} - 5 x + 1 = 8 - 2 x

Move

2 x

to the left side

4 x^{2} - 3 x + 1 = 8

Move

8

to the left side

4 x^{2} - 3 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 4 ( - 7 )}{2 \cdot 4}

(- 3)^{2} - 4 \cdot 4 (- 7) = 11

x_{1, 2} = \frac{- ( - 3 ) \pm 11}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 11}{2 \cdot 4}, x_{2} = \frac{- ( - 3 ) - 11}{2 \cdot 4}

x = \frac{- ( - 3 ) + 11}{2 \cdot 4} : \frac{7}{4}

x = \frac{- ( - 3 ) - 11}{2 \cdot 4} : - 1

The solutions to the quadratic equation are:

x = \frac{7}{4}, x = - 1

(2 x)^{2} - 60 = 5

3 k^{2} - k - 2 = 0

a (x - h)^{2} + k = 0

5 v^{2} + 15 v = 0

x^{2} + 25 = 50

What are the solutions to the equation (4x-1)(x-1)=8-2x ?
The solutions to the equation (4x-1)(x-1)=8-2x are x= 7/4 ,x=-1
Find the zeros of (4x-1)(x-1)=8-2x
The zeros of (4x-1)(x-1)=8-2x are x= 7/4 ,x=-1