What are the solutions to the equation quadraticformula x^2-4x-5=0 ?

The solutions to the equation quadraticformula x^2-4x-5=0 are x=5,x=-1

Find the zeros of quadraticformula x^2-4x-5=0

The zeros of quadraticformula x^2-4x-5=0 are x=5,x=-1

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x^{2} - 4 x - 5 = 0

x = 5, x = - 1

Solution steps

x^{2} - 4 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 5 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 5) = 6

x_{1, 2} = \frac{- ( - 4 ) \pm 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 6}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 6}{2 \cdot 1}

x = \frac{- ( - 4 ) + 6}{2 \cdot 1} : 5

x = \frac{- ( - 4 ) - 6}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

x = 5, x = - 1

2 r^{2} + r - 14 = 0

\frac{3 x + 1}{3} - \frac{5 x ^{2} + 3}{2} = \frac{x ^{2} - 1}{2} - \frac{x + 2}{3}

x, x^{2} + y^{2} = 4 x y

3 x^{2} - 24 x + 40 = 0

x^{2} - 10 = 2 x^{2}

What are the solutions to the equation quadraticformula x^2-4x-5=0 ?
The solutions to the equation quadraticformula x^2-4x-5=0 are x=5,x=-1
Find the zeros of quadraticformula x^2-4x-5=0
The zeros of quadraticformula x^2-4x-5=0 are x=5,x=-1