What are the solutions to the equation 12y-4=9y^2 ?

The solutions to the equation 12y-4=9y^2 are y= 2/3

Find the zeros of 12y-4=9y^2

The zeros of 12y-4=9y^2 are y= 2/3

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12 y - 4 = 9 y^{2}

y = \frac{2}{3}

Decimal Notation

y = 0.66666 \dots

Solution steps

12 y - 4 = 9 y^{2}

Switch sides

9 y^{2} = 12 y - 4

Move

4

to the left side

9 y^{2} + 4 = 12 y

Move

12 y

to the left side

9 y^{2} + 4 - 12 y = 0

Write in the standard form

a x^{2} + b x + c = 0

9 y^{2} - 12 y + 4 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 9 \cdot 4}{2 \cdot 9}

(- 12)^{2} - 4 \cdot 9 \cdot 4 = 0

y_{1, 2} = \frac{- ( - 12 ) \pm 0}{2 \cdot 9}

y = \frac{- ( - 12 )}{2 \cdot 9}

\frac{- ( - 12 )}{2 \cdot 9} = \frac{2}{3}

y = \frac{2}{3}

The solution to the quadratic equation is:

y = \frac{2}{3}

0 = 2 x^{2} + 5 x + 2

y = a (4 a - 5), a = 3

3 x^{2} - 15 x - 12 = 0

4 x^{2} - 0.2 = 0

- 6 x^{2} + 5 = - 4 x + 8

What are the solutions to the equation 12y-4=9y^2 ?
The solutions to the equation 12y-4=9y^2 are y= 2/3
Find the zeros of 12y-4=9y^2
The zeros of 12y-4=9y^2 are y= 2/3