What are the solutions to the equation -x^2+x+7=0 ?

The solutions to the equation -x^2+x+7=0 are x=-(-1+sqrt(29))/2 ,x=(1+sqrt(29))/2

Find the zeros of -x^2+x+7=0

The zeros of -x^2+x+7=0 are x=-(-1+sqrt(29))/2 ,x=(1+sqrt(29))/2

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- x^{2} + x + 7 = 0

x = - \frac{- 1 + 29}{2}, x = \frac{1 + 29}{2}

Decimal Notation

x = - 2.19258 \dots, x = 3.19258 \dots

Solution steps

- x^{2} + x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 1 ) \cdot 7}{2 ( - 1 )}

1^{2} - 4 (- 1) \cdot 7 = 29

x_{1, 2} = \frac{- 1 \pm 29}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 1 + 29}{2 ( - 1 )}, x_{2} = \frac{- 1 - 29}{2 ( - 1 )}

x = \frac{- 1 + 29}{2 ( - 1 )} : - \frac{- 1 + 29}{2}

x = \frac{- 1 - 29}{2 ( - 1 )} : \frac{1 + 29}{2}

The solutions to the quadratic equation are:

x = - \frac{- 1 + 29}{2}, x = \frac{1 + 29}{2}

x^{2} + 12 x + 36 = 0

- y^{2} = 1

x, x^{2} + y^{2} + 20 x + 2 y + 102 = 0

x^{2} + 4 x + 3 x = 0

2 x^{2} + 6 x - 5

What are the solutions to the equation -x^2+x+7=0 ?
The solutions to the equation -x^2+x+7=0 are x=-(-1+sqrt(29))/2 ,x=(1+sqrt(29))/2
Find the zeros of -x^2+x+7=0
The zeros of -x^2+x+7=0 are x=-(-1+sqrt(29))/2 ,x=(1+sqrt(29))/2