What are the solutions to the equation 20-x=x^2 ?

The solutions to the equation 20-x=x^2 are x=4,x=-5

Find the zeros of 20-x=x^2

The zeros of 20-x=x^2 are x=4,x=-5

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20 - x = x^{2}

x = 4, x = - 5

Solution steps

20 - x = x^{2}

Switch sides

x^{2} = 20 - x

Move

x

to the left side

x^{2} + x = 20

Move

20

to the left side

x^{2} + x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 20 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 20) = 9

x_{1, 2} = \frac{- 1 \pm 9}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 9}{2 \cdot 1}, x_{2} = \frac{- 1 - 9}{2 \cdot 1}

x = \frac{- 1 + 9}{2 \cdot 1} : 4

x = \frac{- 1 - 9}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

x = 4, x = - 5

5 x^{2} - 5 x - 60 = 0

x^{2} + 4 x - 11

x^{2} + 4 x - 21

0 = 4 x^{2} + 36

x^{2} + 12 = 37

What are the solutions to the equation 20-x=x^2 ?
The solutions to the equation 20-x=x^2 are x=4,x=-5
Find the zeros of 20-x=x^2
The zeros of 20-x=x^2 are x=4,x=-5