What are the solutions to the equation 2x^2-14x+9=0 ?

The solutions to the equation 2x^2-14x+9=0 are x=(7+sqrt(31))/2 ,x=(7-sqrt(31))/2

Find the zeros of 2x^2-14x+9=0

The zeros of 2x^2-14x+9=0 are x=(7+sqrt(31))/2 ,x=(7-sqrt(31))/2

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2 x^{2} - 14 x + 9 = 0

x = \frac{7 + 31}{2}, x = \frac{7 - 31}{2}

Decimal Notation

x = 6.28388 \dots, x = 0.71611 \dots

Solution steps

2 x^{2} - 14 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 2 \cdot 9}{2 \cdot 2}

(- 14)^{2} - 4 \cdot 2 \cdot 9 = 231

x_{1, 2} = \frac{- ( - 14 ) \pm 2 31}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 2 31}{2 \cdot 2}, x_{2} = \frac{- ( - 14 ) - 2 31}{2 \cdot 2}

x = \frac{- ( - 14 ) + 2 31}{2 \cdot 2} : \frac{7 + 31}{2}

x = \frac{- ( - 14 ) - 2 31}{2 \cdot 2} : \frac{7 - 31}{2}

The solutions to the quadratic equation are:

x = \frac{7 + 31}{2}, x = \frac{7 - 31}{2}

400 - x^{2} = 20 x + 100

x, 20 m^{2} = (2 x + 6 m) x

2 x^{2} = 75 - 5 x

\frac{1}{4} x^{2} = 0

- 3 x^{2} + 2 x + 1

What are the solutions to the equation 2x^2-14x+9=0 ?
The solutions to the equation 2x^2-14x+9=0 are x=(7+sqrt(31))/2 ,x=(7-sqrt(31))/2
Find the zeros of 2x^2-14x+9=0
The zeros of 2x^2-14x+9=0 are x=(7+sqrt(31))/2 ,x=(7-sqrt(31))/2