What are the solutions to the equation 2y^2-7y=7 ?

The solutions to the equation 2y^2-7y=7 are y=(7+sqrt(105))/4 ,y=(7-sqrt(105))/4

Find the zeros of 2y^2-7y=7

The zeros of 2y^2-7y=7 are y=(7+sqrt(105))/4 ,y=(7-sqrt(105))/4

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2 y^{2} - 7 y = 7

y = \frac{7 + 105}{4}, y = \frac{7 - 105}{4}

Decimal Notation

y = 4.31173 \dots, y = - 0.81173 \dots

Solution steps

2 y^{2} - 7 y = 7

Move

7

to the left side

2 y^{2} - 7 y - 7 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 2 ( - 7 )}{2 \cdot 2}

(- 7)^{2} - 4 \cdot 2 (- 7) = 105

y_{1, 2} = \frac{- ( - 7 ) \pm 105}{2 \cdot 2}

Separate the solutions

y_{1} = \frac{- ( - 7 ) + 105}{2 \cdot 2}, y_{2} = \frac{- ( - 7 ) - 105}{2 \cdot 2}

y = \frac{- ( - 7 ) + 105}{2 \cdot 2} : \frac{7 + 105}{4}

y = \frac{- ( - 7 ) - 105}{2 \cdot 2} : \frac{7 - 105}{4}

The solutions to the quadratic equation are:

y = \frac{7 + 105}{4}, y = \frac{7 - 105}{4}

0.09 x^{2} = 1

665 - 216 x + 12 x^{2} = 0

(x - 5) (x - 8) = 8

(3 n - 1) x^{2} + 7 = 4 n x

14 x^{2} + x - 26 = 2 x^{2} - 4

What are the solutions to the equation 2y^2-7y=7 ?
The solutions to the equation 2y^2-7y=7 are y=(7+sqrt(105))/4 ,y=(7-sqrt(105))/4
Find the zeros of 2y^2-7y=7
The zeros of 2y^2-7y=7 are y=(7+sqrt(105))/4 ,y=(7-sqrt(105))/4