What are the solutions to the equation 5x^2+5x=-1 ?

The solutions to the equation 5x^2+5x=-1 are x=(-sqrt(5)+1)/(2sqrt(5)),x=-(sqrt(5)+1)/(2sqrt(5))

Find the zeros of 5x^2+5x=-1

The zeros of 5x^2+5x=-1 are x=(-sqrt(5)+1)/(2sqrt(5)),x=-(sqrt(5)+1)/(2sqrt(5))

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5 x^{2} + 5 x = - 1

x = \frac{- 5 + 1}{2 5}, x = - \frac{5 + 1}{2 5}

Decimal Notation

x = - 0.27639 \dots, x = - 0.72360 \dots

Solution steps

5 x^{2} + 5 x = - 1

Move

1

to the left side

5 x^{2} + 5 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 5 \cdot 1}{2 \cdot 5}

5^{2} - 4 \cdot 5 \cdot 1 = 5

x_{1, 2} = \frac{- 5 \pm 5}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 5 + 5}{2 \cdot 5}, x_{2} = \frac{- 5 - 5}{2 \cdot 5}

x = \frac{- 5 + 5}{2 \cdot 5} : \frac{- 5 + 1}{2 5}

x = \frac{- 5 - 5}{2 \cdot 5} : - \frac{5 + 1}{2 5}

The solutions to the quadratic equation are:

x = \frac{- 5 + 1}{2 5}, x = - \frac{5 + 1}{2 5}

x^{2} + 11 x = 28

x^{2} - 6 x = 72

x, f = I n (x^{2} + 1)

0 = x^{2} - x - 4

(w + 5)^{2} - 54 = 0

What are the solutions to the equation 5x^2+5x=-1 ?
The solutions to the equation 5x^2+5x=-1 are x=(-sqrt(5)+1)/(2sqrt(5)),x=-(sqrt(5)+1)/(2sqrt(5))
Find the zeros of 5x^2+5x=-1
The zeros of 5x^2+5x=-1 are x=(-sqrt(5)+1)/(2sqrt(5)),x=-(sqrt(5)+1)/(2sqrt(5))