What are the solutions to the equation n^2+6n+2=0 ?

The solutions to the equation n^2+6n+2=0 are n=-3+sqrt(7),n=-3-sqrt(7)

Find the zeros of n^2+6n+2=0

The zeros of n^2+6n+2=0 are n=-3+sqrt(7),n=-3-sqrt(7)

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n^{2} + 6 n + 2 = 0

n = - 3 + 7, n = - 3 - 7

Decimal Notation

n = - 0.35424 \dots, n = - 5.64575 \dots

Solution steps

n^{2} + 6 n + 2 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot 2 = 27

n_{1, 2} = \frac{- 6 \pm 2 7}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- 6 + 2 7}{2 \cdot 1}, n_{2} = \frac{- 6 - 2 7}{2 \cdot 1}

n = \frac{- 6 + 2 7}{2 \cdot 1} : - 3 + 7

n = \frac{- 6 - 2 7}{2 \cdot 1} : - 3 - 7

The solutions to the quadratic equation are:

n = - 3 + 7, n = - 3 - 7

z^{2} + 25 = 0

x^{2} + 10 x = 9

(x) (x + 3) = 54

x^{2} - 4 x - 8 = - 8

20 x^{2} - 10 x = 0

What are the solutions to the equation n^2+6n+2=0 ?
The solutions to the equation n^2+6n+2=0 are n=-3+sqrt(7),n=-3-sqrt(7)
Find the zeros of n^2+6n+2=0
The zeros of n^2+6n+2=0 are n=-3+sqrt(7),n=-3-sqrt(7)