What are the solutions to the equation X^2+5X+4=0 ?

The solutions to the equation X^2+5X+4=0 are X=-1,X=-4

Find the zeros of X^2+5X+4=0

The zeros of X^2+5X+4=0 are X=-1,X=-4

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X^{2} + 5 X + 4 = 0

X = - 1, X = - 4

Solution steps

X^{2} + 5 X + 4 = 0

Solve with the quadratic formula

X_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot 4 = 3

X_{1, 2} = \frac{- 5 \pm 3}{2 \cdot 1}

Separate the solutions

X_{1} = \frac{- 5 + 3}{2 \cdot 1}, X_{2} = \frac{- 5 - 3}{2 \cdot 1}

X = \frac{- 5 + 3}{2 \cdot 1} : - 1

X = \frac{- 5 - 3}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

X = - 1, X = - 4

x^{2} + 39 x = 0

x^{2} - 9 = x - 3

12 x^{2} - 78 x + 90 = 0

6 x^{2} - 31 x + 35 = 0

x, x^{2} - 4 x y + 4 y^{2} = 0

What are the solutions to the equation X^2+5X+4=0 ?
The solutions to the equation X^2+5X+4=0 are X=-1,X=-4
Find the zeros of X^2+5X+4=0
The zeros of X^2+5X+4=0 are X=-1,X=-4