What are the solutions to the equation p^2-8p=0 ?

The solutions to the equation p^2-8p=0 are p=8,p=0

Find the zeros of p^2-8p=0

The zeros of p^2-8p=0 are p=8,p=0

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p^{2} - 8 p = 0

p = 8, p = 0

Solution steps

p^{2} - 8 p = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 0 = 8

p_{1, 2} = \frac{- ( - 8 ) \pm 8}{2 \cdot 1}

Separate the solutions

p_{1} = \frac{- ( - 8 ) + 8}{2 \cdot 1}, p_{2} = \frac{- ( - 8 ) - 8}{2 \cdot 1}

p = \frac{- ( - 8 ) + 8}{2 \cdot 1} : 8

p = \frac{- ( - 8 ) - 8}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

p = 8, p = 0

r, x^{2} + y^{2} + z^{2} = r^{2}

9 x^{2} - 6 a^{2} x - b^{4} + a^{4} = 0

24 x^{2} + 18 x = 0

3 x^{2} + 15 x + 2 = 0

x, x^{2} + 2 y^{2} - 6 x - 8 y + 21 = 0

What are the solutions to the equation p^2-8p=0 ?
The solutions to the equation p^2-8p=0 are p=8,p=0
Find the zeros of p^2-8p=0
The zeros of p^2-8p=0 are p=8,p=0