What are the solutions to the equation -3t(t+2)=-7 ?

The solutions to the equation -3t(t+2)=-7 are t=-(3+sqrt(30))/3 ,t=(sqrt(30)-3)/3

Find the zeros of -3t(t+2)=-7

The zeros of -3t(t+2)=-7 are t=-(3+sqrt(30))/3 ,t=(sqrt(30)-3)/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 3 t (t + 2) = - 7

t = - \frac{3 + 30}{3}, t = \frac{30 - 3}{3}

Decimal Notation

t = - 2.82574 \dots, t = 0.82574 \dots

Solution steps

- 3 t (t + 2) = - 7

Expand

- 3 t (t + 2) : - 3 t^{2} - 6 t

- 3 t^{2} - 6 t = - 7

Move

7

to the left side

- 3 t^{2} - 6 t + 7 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 ( - 3 ) \cdot 7}{2 ( - 3 )}

(- 6)^{2} - 4 (- 3) \cdot 7 = 230

t_{1, 2} = \frac{- ( - 6 ) \pm 2 30}{2 ( - 3 )}

Separate the solutions

t_{1} = \frac{- ( - 6 ) + 2 30}{2 ( - 3 )}, t_{2} = \frac{- ( - 6 ) - 2 30}{2 ( - 3 )}

t = \frac{- ( - 6 ) + 2 30}{2 ( - 3 )} : - \frac{3 + 30}{3}

t = \frac{- ( - 6 ) - 2 30}{2 ( - 3 )} : \frac{30 - 3}{3}

The solutions to the quadratic equation are:

t = - \frac{3 + 30}{3}, t = \frac{30 - 3}{3}

2 x^{2} + 7 x + 7

x^{2} - 10 x + 52 = 0

x^{2} + 4 = x + 6

3 x^{2} - 81 x = 0

x, - 4 x^{2} - 42 x + 22 = 0

What are the solutions to the equation -3t(t+2)=-7 ?
The solutions to the equation -3t(t+2)=-7 are t=-(3+sqrt(30))/3 ,t=(sqrt(30)-3)/3
Find the zeros of -3t(t+2)=-7
The zeros of -3t(t+2)=-7 are t=-(3+sqrt(30))/3 ,t=(sqrt(30)-3)/3