What are the solutions to the equation 4x^2-6x+9/4 =0 ?

The solutions to the equation 4x^2-6x+9/4 =0 are x= 3/4

Find the zeros of 4x^2-6x+9/4 =0

The zeros of 4x^2-6x+9/4 =0 are x= 3/4

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4 x^{2} - 6 x + \frac{9}{4} = 0

x = \frac{3}{4}

Decimal Notation

x = 0.75

Solution steps

4 x^{2} - 6 x + \frac{9}{4} = 0

Multiply both sides by

4

16 x^{2} - 24 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 16 \cdot 9}{2 \cdot 16}

(- 24)^{2} - 4 \cdot 16 \cdot 9 = 0

x_{1, 2} = \frac{- ( - 24 ) \pm 0}{2 \cdot 16}

x = \frac{- ( - 24 )}{2 \cdot 16}

\frac{- ( - 24 )}{2 \cdot 16} = \frac{3}{4}

x = \frac{3}{4}

The solution to the quadratic equation is:

x = \frac{3}{4}

x, y = x^{2} - 2 x + 1

2 x^{2} + 4 = 2 (x + 2) - 3 x^{2}

\frac{( y + 1 ) ^{2}}{49} = 1

T^{1} = \frac{9}{5} T^{2} + 32

t^{2} - 4 t + 1 = 0

What are the solutions to the equation 4x^2-6x+9/4 =0 ?
The solutions to the equation 4x^2-6x+9/4 =0 are x= 3/4
Find the zeros of 4x^2-6x+9/4 =0
The zeros of 4x^2-6x+9/4 =0 are x= 3/4