What are the solutions to the equation r^2+490=0 ?

The solutions to the equation r^2+490=0 are r=sqrt(10)*7i,r=-sqrt(10)*7i

Find the zeros of r^2+490=0

The zeros of r^2+490=0 are r=sqrt(10)*7i,r=-sqrt(10)*7i

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r^{2} + 490 = 0

r = 10 \cdot 7 i, r = - 10 \cdot 7 i

Solution steps

r^{2} + 490 = 0

Move

490

to the right side

r^{2} = - 490

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

r = - 490, r = - - 490

- 490 = 10 \cdot 7 i

- - 490 = - 10 \cdot 7 i

r = 10 \cdot 7 i, r = - 10 \cdot 7 i

256 c^{2} = 169

- 8 x^{2} - 16 x = 0

- 6 x^{2} + 10 x = 0

a, a^{2} = b^{2} \frac{1}{2}

a^{2} + 10 = 110

What are the solutions to the equation r^2+490=0 ?
The solutions to the equation r^2+490=0 are r=sqrt(10)*7i,r=-sqrt(10)*7i
Find the zeros of r^2+490=0
The zeros of r^2+490=0 are r=sqrt(10)*7i,r=-sqrt(10)*7i