What are the solutions to the equation c^2-6c-7=0 ?

The solutions to the equation c^2-6c-7=0 are c=7,c=-1

Find the zeros of c^2-6c-7=0

The zeros of c^2-6c-7=0 are c=7,c=-1

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c^{2} - 6 c - 7 = 0

c = 7, c = - 1

Solution steps

c^{2} - 6 c - 7 = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot ( - 7 )}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot (- 7) = 8

c_{1, 2} = \frac{- ( - 6 ) \pm 8}{2 \cdot 1}

Separate the solutions

c_{1} = \frac{- ( - 6 ) + 8}{2 \cdot 1}, c_{2} = \frac{- ( - 6 ) - 8}{2 \cdot 1}

c = \frac{- ( - 6 ) + 8}{2 \cdot 1} : 7

c = \frac{- ( - 6 ) - 8}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

c = 7, c = - 1

x, 3 x^{2} - 4 x y + 2 y^{2} = 17

(2 x + 4) (x - 4) = 0

5 x^{2} - 33 x + 18 = 0

9 x^{2} - 7 = - 44

x, x^{2} + y^{2} - 2 x - 20 y + 105 = 0

What are the solutions to the equation c^2-6c-7=0 ?
The solutions to the equation c^2-6c-7=0 are c=7,c=-1
Find the zeros of c^2-6c-7=0
The zeros of c^2-6c-7=0 are c=7,c=-1