What are the solutions to the equation (x-1)(x+5)=7 ?

The solutions to the equation (x-1)(x+5)=7 are x=2,x=-6

Find the zeros of (x-1)(x+5)=7

The zeros of (x-1)(x+5)=7 are x=2,x=-6

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(x - 1) (x + 5) = 7

x = 2, x = - 6

Solution steps

(x - 1) (x + 5) = 7

Expand

(x - 1) (x + 5) : x^{2} + 4 x - 5

x^{2} + 4 x - 5 = 7

Move

7

to the left side

x^{2} + 4 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 12 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 12) = 8

x_{1, 2} = \frac{- 4 \pm 8}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 8}{2 \cdot 1}, x_{2} = \frac{- 4 - 8}{2 \cdot 1}

x = \frac{- 4 + 8}{2 \cdot 1} : 2

x = \frac{- 4 - 8}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

x = 2, x = - 6

x (2 x - 5) - 5 = x (x - 1)

4 x^{2} - 16 = 0

\frac{1}{4} m^{2} + \frac{3}{5} m = - \frac{1}{4}

0 = - \frac{2}{3} (x - 1) (x + 3)

7 x^{2} = 22 x - 3

What are the solutions to the equation (x-1)(x+5)=7 ?
The solutions to the equation (x-1)(x+5)=7 are x=2,x=-6
Find the zeros of (x-1)(x+5)=7
The zeros of (x-1)(x+5)=7 are x=2,x=-6