What are the solutions to the equation 5x^2+4=3 ?

The solutions to the equation 5x^2+4=3 are x= 1/(sqrt(5))i,x=-1/(sqrt(5))i

Find the zeros of 5x^2+4=3

The zeros of 5x^2+4=3 are x= 1/(sqrt(5))i,x=-1/(sqrt(5))i

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5 x^{2} + 4 = 3

x = \frac{1}{5} i, x = - \frac{1}{5} i

Solution steps

5 x^{2} + 4 = 3

Move

4

to the right side

5 x^{2} = - 1

Divide both sides by

5

x^{2} = - \frac{1}{5}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{1}{5}, x = - - \frac{1}{5}

- \frac{1}{5} = \frac{1}{5} i

- - \frac{1}{5} = - \frac{1}{5} i

x = \frac{1}{5} i, x = - \frac{1}{5} i

5 x^{2} - 1 = 3 x^{2}

x, 4 x^{2} + x y = 16

x^{2} + 7 x + 4 = 0

(x + 5)^{2} - 16 = 0

(3 x)^{2} + (4 x)^{2} = 7 5^{2}

What are the solutions to the equation 5x^2+4=3 ?
The solutions to the equation 5x^2+4=3 are x= 1/(sqrt(5))i,x=-1/(sqrt(5))i
Find the zeros of 5x^2+4=3
The zeros of 5x^2+4=3 are x= 1/(sqrt(5))i,x=-1/(sqrt(5))i