What are the solutions to the equation u^2-23u+22=0 ?

The solutions to the equation u^2-23u+22=0 are u=22,u=1

Find the zeros of u^2-23u+22=0

The zeros of u^2-23u+22=0 are u=22,u=1

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u^{2} - 23 u + 22 = 0

u = 22, u = 1

Solution steps

u^{2} - 23 u + 22 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- ( - 23 ) \pm ( - 23 ) ^{2} - 4 \cdot 1 \cdot 22}{2 \cdot 1}

(- 23)^{2} - 4 \cdot 1 \cdot 22 = 21

u_{1, 2} = \frac{- ( - 23 ) \pm 21}{2 \cdot 1}

Separate the solutions

u_{1} = \frac{- ( - 23 ) + 21}{2 \cdot 1}, u_{2} = \frac{- ( - 23 ) - 21}{2 \cdot 1}

u = \frac{- ( - 23 ) + 21}{2 \cdot 1} : 22

u = \frac{- ( - 23 ) - 21}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

u = 22, u = 1

5 x^{3} + 10 x^{2} - 20 x - 40

(\frac{3}{4})^{- 3}

\frac{6}{10} \cdot \frac{5}{9}

5 b^{2} \cdot 8 b

\frac{10}{4} \cdot \frac{2}{25}

What are the solutions to the equation u^2-23u+22=0 ?
The solutions to the equation u^2-23u+22=0 are u=22,u=1
Find the zeros of u^2-23u+22=0
The zeros of u^2-23u+22=0 are u=22,u=1