What are the solutions to the equation -x^2-10x+25=0 ?

The solutions to the equation -x^2-10x+25=0 are x=-5(1+sqrt(2)),x=5(sqrt(2)-1)

Find the zeros of -x^2-10x+25=0

The zeros of -x^2-10x+25=0 are x=-5(1+sqrt(2)),x=5(sqrt(2)-1)

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- x^{2} - 10 x + 25 = 0

x = - 5 (1 + 2), x = 5 (2 - 1)

Decimal Notation

x = - 12.07106 \dots, x = 2.07106 \dots

Solution steps

- x^{2} - 10 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 ( - 1 ) \cdot 25}{2 ( - 1 )}

(- 10)^{2} - 4 (- 1) \cdot 25 = 102

x_{1, 2} = \frac{- ( - 10 ) \pm 10 2}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 10 2}{2 ( - 1 )}, x_{2} = \frac{- ( - 10 ) - 10 2}{2 ( - 1 )}

x = \frac{- ( - 10 ) + 10 2}{2 ( - 1 )} : - 5 (1 + 2)

x = \frac{- ( - 10 ) - 10 2}{2 ( - 1 )} : 5 (2 - 1)

The solutions to the quadratic equation are:

x = - 5 (1 + 2), x = 5 (2 - 1)

3 c^{2} + 1 = 5

x^{2} + x - 144 = 0

3 x^{2} - 24 x + 60 = 0

y^{2} - 6 y - 10 = 0

3 x^{2} - 4 x = 6 x - 3

What are the solutions to the equation -x^2-10x+25=0 ?
The solutions to the equation -x^2-10x+25=0 are x=-5(1+sqrt(2)),x=5(sqrt(2)-1)
Find the zeros of -x^2-10x+25=0
The zeros of -x^2-10x+25=0 are x=-5(1+sqrt(2)),x=5(sqrt(2)-1)