What are the solutions to the equation x^2+0x+4=0 ?

The solutions to the equation x^2+0x+4=0 are x=2i,x=-2i

Find the zeros of x^2+0x+4=0

The zeros of x^2+0x+4=0 are x=2i,x=-2i

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x^{2} + 0 x + 4 = 0

x = 2 i, x = - 2 i

Solution steps

x^{2} + 0 \cdot x + 4 = 0

Refine

x^{2} + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 0 \pm 0 ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

Simplify

0^{2} - 4 \cdot 1 \cdot 4 : 4 i

x_{1, 2} = \frac{- 0 \pm 4 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 0 + 4 i}{2 \cdot 1}, x_{2} = \frac{- 0 - 4 i}{2 \cdot 1}

x = \frac{- 0 + 4 i}{2 \cdot 1} : 2 i

x = \frac{- 0 - 4 i}{2 \cdot 1} : - 2 i

The solutions to the quadratic equation are:

x = 2 i, x = - 2 i

36 x^{2} - 72 x

10 y^{2} - 126 y + 5 = 0

3 x^{2} + 6 x = 0

(x - 4)^{2} = 11

x^{2} - 9 x + 2 = 0

What are the solutions to the equation x^2+0x+4=0 ?
The solutions to the equation x^2+0x+4=0 are x=2i,x=-2i
Find the zeros of x^2+0x+4=0
The zeros of x^2+0x+4=0 are x=2i,x=-2i