What are the solutions to the equation 6(x+8)(8x+1)=0 ?

The solutions to the equation 6(x+8)(8x+1)=0 are x=-8,x=-1/8

Find the zeros of 6(x+8)(8x+1)=0

The zeros of 6(x+8)(8x+1)=0 are x=-8,x=-1/8

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6 (x + 8) (8 x + 1) = 0

x = - 8, x = - \frac{1}{8}

Decimal Notation

x = - 8, x = - 0.125

Solution steps

6 (x + 8) (8 x + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 8 = 0 or 8 x + 1 = 0

Solve

x + 8 = 0 : x = - 8

Solve

8 x + 1 = 0 : x = - \frac{1}{8}

The solutions to the quadratic equation are:

x = - 8, x = - \frac{1}{8}

x^{2} + 14 x - 75 = - 3

9 - (\frac{x}{2})^{2} = 6 - x

x^{2} - 4 x + 1 (m + 1) = 0.8

x^{2} = - 7 x - 12

x^{2} = - 7 x - 10

What are the solutions to the equation 6(x+8)(8x+1)=0 ?
The solutions to the equation 6(x+8)(8x+1)=0 are x=-8,x=-1/8
Find the zeros of 6(x+8)(8x+1)=0
The zeros of 6(x+8)(8x+1)=0 are x=-8,x=-1/8