What are the solutions to the equation v^2+10v+21=0 ?

The solutions to the equation v^2+10v+21=0 are v=-3,v=-7

Find the zeros of v^2+10v+21=0

The zeros of v^2+10v+21=0 are v=-3,v=-7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

v^{2} + 10 v + 21 = 0

v = - 3, v = - 7

Solution steps

v^{2} + 10 v + 21 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 21}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 21 = 4

v_{1, 2} = \frac{- 10 \pm 4}{2 \cdot 1}

Separate the solutions

v_{1} = \frac{- 10 + 4}{2 \cdot 1}, v_{2} = \frac{- 10 - 4}{2 \cdot 1}

v = \frac{- 10 + 4}{2 \cdot 1} : - 3

v = \frac{- 10 - 4}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

v = - 3, v = - 7

(\frac{1}{2} x + 7)^{2} + 7 (\frac{1}{2} x + 7) + 12 = 0

3 + in (x^{2} + 1) = 2 in (x)

4 x^{2} - a^{2} = 0

(x + 2) (x + 1) - (x - 1) = 6

0 = - \frac{32}{81} (x^{2} - x - 20)

What are the solutions to the equation v^2+10v+21=0 ?
The solutions to the equation v^2+10v+21=0 are v=-3,v=-7
Find the zeros of v^2+10v+21=0
The zeros of v^2+10v+21=0 are v=-3,v=-7