What are the solutions to the equation x+15=x(x-1) ?

The solutions to the equation x+15=x(x-1) are x=5,x=-3

Find the zeros of x+15=x(x-1)

The zeros of x+15=x(x-1) are x=5,x=-3

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x + 15 = x (x - 1)

x = 5, x = - 3

Solution steps

x + 15 = x (x - 1)

Expand

x (x - 1) : x^{2} - x

x + 15 = x^{2} - x

Switch sides

x^{2} - x = x + 15

Move

15

to the left side

x^{2} - x - 15 = x

Move

x

to the left side

x^{2} - 2 x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 15 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 15) = 8

x_{1, 2} = \frac{- ( - 2 ) \pm 8}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 8}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 8}{2 \cdot 1}

x = \frac{- ( - 2 ) + 8}{2 \cdot 1} : 5

x = \frac{- ( - 2 ) - 8}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

x = 5, x = - 3

(2 x + 1) (x - 4) - 10 = 0

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0.544 x^{2} - 4.9 x + 7.385 = 0

4 x^{2} + 4 x + 6 = 0

3 x^{2} - 18 x + 24 = 0

What are the solutions to the equation x+15=x(x-1) ?
The solutions to the equation x+15=x(x-1) are x=5,x=-3
Find the zeros of x+15=x(x-1)
The zeros of x+15=x(x-1) are x=5,x=-3