What are the solutions to the equation 3x^2+18x+7=-8 ?

The solutions to the equation 3x^2+18x+7=-8 are x=-1,x=-5

Find the zeros of 3x^2+18x+7=-8

The zeros of 3x^2+18x+7=-8 are x=-1,x=-5

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3 x^{2} + 18 x + 7 = - 8

x = - 1, x = - 5

Solution steps

3 x^{2} + 18 x + 7 = - 8

Move

8

to the left side

3 x^{2} + 18 x + 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 3 \cdot 15}{2 \cdot 3}

1 8^{2} - 4 \cdot 3 \cdot 15 = 12

x_{1, 2} = \frac{- 18 \pm 12}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 18 + 12}{2 \cdot 3}, x_{2} = \frac{- 18 - 12}{2 \cdot 3}

x = \frac{- 18 + 12}{2 \cdot 3} : - 1

x = \frac{- 18 - 12}{2 \cdot 3} : - 5

The solutions to the quadratic equation are:

x = - 1, x = - 5

25 x^{2} + 50 x + 169 = 0

x^{2} - 49 x + 558 = 0

3 x^{2} - 2 = - 29

2 x^{2} + 8 x + 1

x^{2} + b x + c = 0, x^{2} + c x + b = 0

What are the solutions to the equation 3x^2+18x+7=-8 ?
The solutions to the equation 3x^2+18x+7=-8 are x=-1,x=-5
Find the zeros of 3x^2+18x+7=-8
The zeros of 3x^2+18x+7=-8 are x=-1,x=-5